Problem 89 Alanine, abbreviated HAla, is an... [FREE SOLUTION] (2025)

Chapter 15: Problem 89

Alanine, abbreviated HAla, is an amino acid in protein. If \(21.05\mathrm{~mL}\) of \(0.145 \mathrm{M}\) NaOH neutralizes \(0.272 \mathrm{~g}\) HAla,what is the molar mass of the amino acid?

Short Answer

Expert verified

The molar mass of alanine is approximately 89.09 g/mol.

Step by step solution

01

Determine Moles of NaOH

We start with the volume and concentration of NaOH. The formula for calculating moles is: \( ext{moles} = ext{concentration (M)} \times \text{volume (L)} \). Convert the volume from milliliters to liters: \( 21.05 \text{ mL} = 0.02105 \text{ L} \). Calculate moles of NaOH: \( 0.145 \text{ M} \times 0.02105 \text{ L} = 0.00305225 \text{ moles} \).

02

Relate Moles of NaOH to Moles of HAla

In the neutralization reaction, one mole of NaOH reacts with one mole of HAla since alanine is a monoprotic acid. Therefore, the moles of HAla will be the same as the moles of NaOH: \( 0.00305225 \text{ moles HAla} \).

03

Calculate Molar Mass of HAla

Use the formula for molar mass: \( \text{molar mass} = \frac{\text{mass of HAla}}{\text{moles of HAla}} \). The mass of HAla given is \( 0.272 \text{ g} \). So, the molar mass is: \( \frac{0.272 \text{ g}}{0.00305225 \text{ moles}} \approx 89.09 \text{ g/mol} \).

Problem 89 Alanine, abbreviated HAla, is an... [FREE SOLUTION] (1)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amino Acids

Amino acids are the building blocks of proteins, crucial for various biological functions in living organisms. Each amino acid consists of:

  • An amino group \(-NH_2\)
  • A carboxyl group \(-COOH\)
  • A side chain, which makes each amino acid unique

These compounds are essential for the synthesis of proteins and other important molecules like enzymes and neurotransmitters.
In biochemical processes, amino acids can act as energy sources, precursors for biosynthesis, and perform other central roles in metabolism. Alanine, as discussed in this exercise, is one such amino acid, important for protein formation and energy production.

Neutralization Reaction

A neutralization reaction is a chemical reaction where an acid and a base react to form water and a salt. The general formula for this process is:\[ \text{H}^+ + \text{OH}^- \rightarrow \text{H}_2\text{O} \]

  • Acids provide hydrogen ions \((H^+)\)
  • Bases provide hydroxide ions \((OH^-)\)

This reaction is essential in various fields, including medicine and environmental science.
In the context of our exercise, alanine (HAla), which contains an acidic group, reacts with \(ext{NaOH}\) (a base) to achieve neutralization. Here, one mole of \(ext{NaOH}\) neutralizes one mole of alanine, illustrating a key aspect of neutralization reactions involving equal molar quantities.

Alanine

Alanine (HAla) is a simple, yet important amino acid with the chemical formula \(\text{C}_3\text{H}_7\text{NO}_2\). It is classified as a non-essential amino acid, meaning that our bodies can produce it without consuming it through the diet.
In metabolic contexts, alanine plays a part in the glucose-alanine cycle, which helps regulate blood sugar levels and remove ammonia, a toxic substance.

  • It's involved in the synthesis of proteins.
  • Acts as a key transporter of nitrogen in the bloodstream.
  • Can be converted into pyruvate in metabolic processes.

Through the exercise in this topic, we calculate the molar mass of alanine by neutralizing it with a known concentration of \(\text{NaOH}\), demonstrating its role in chemical reactions.

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Problem 89 Alanine, abbreviated HAla, is an... [FREE SOLUTION] (3)

Most popular questions from this chapter

Calculate the molar hydrogen ion concentration of each of the following giventhe \(\mathrm{pH}\) : (a) shampoo, \(\mathrm{pH} 6\) (b) pH-balanced shampoo, \(\mathrm{pH} 8\)What is the color of bromthymol blue indicator in a solution of \(\mathrm{pH} 7?\)What volume of \(0.167 M\) barium hydroxide is required to neutralize \(1.655\mathrm{~g}\) of potassium hydrogen phthalate, \(\mathrm{KHC}_{8} \mathrm{H}_{4}\mathrm{O}_{4}(204.23 \mathrm{~g} / \mathrm{mol}) ?\) $$ \begin{array}{r} 2 \mathrm{KHC}_{8} \mathrm{H}_{4} \mathrm{O}_{4}(aq)+\mathrm{Ba}(\mathrm{OH})_{2}(a q) \longrightarrow \\ \mathrm{BaK}_{2}\left(\mathrm{C}_{8} \mathrm{H}_{4}\mathrm{O}_{4}\right)_{2}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l) \end{array} $$Classify each of the following as an Arrhenius acid, an Arrhenius base, or asalt: (a) \(\mathrm{HNO}_{3}(a q)\) (b) \(\mathrm{KNO}_{3}(a q)\) (c) \(\mathrm{KOH}(a q)\) (d) \(\mathrm{K}_{2} \mathrm{CO}_{3}(a q)\)Classify each of the following Arrhenius acids as strong or weak given thedegree of ionization: (a) acetic acid, \(\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q), \sim 1\%\) (b) carbonic acid, \(\mathrm{H}_{2} \mathrm{CO}_{3}(a q), \sim 1 \%\) (c) chlorous acid, \(\mathrm{HClO}_{2}(a q), \sim 1 \%\) (d) chloric acid, \(\mathrm{HClO}_{3}(a q), \sim 100 \%\)
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Problem 89 Alanine, abbreviated HAla, is an... [FREE SOLUTION] (2025)
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